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An alkali metal hydride (NaH) reacts wit...

An alkali metal hydride (NaH) reacts with diborane is 'A' to give a tetrahedral compound 'B' which is extensilve used as reducing agent in organic synthesis. The compoun d 'A' and'B' respectively. Are

A

`(CH_(3) COCH_(3)` and `B_(3)N_(3) H_(6)`

B

`(C_(2)H_(5))_(2) O` and `NaBH_(4)`

C

`C_(2)H_(6)` and `C_(2)H_(5)Na`

D

`C_(6)H_(6)` and `NaBH_(4)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we need to identify the compounds 'A' and 'B' based on the information provided. Here's the step-by-step solution: ### Step 1: Identify the Reactants The question states that an alkali metal hydride, specifically sodium hydride (NaH), reacts with diborane (B2H6). ### Step 2: Determine the Reaction When sodium hydride reacts with diborane, the product formed is sodium borohydride (NaBH4). This is a well-known reaction in inorganic chemistry. ### Step 3: Identify the Solvent The reaction typically occurs in a solvent. In this case, the solvent used is diethyl ether (commonly referred to simply as ether). ### Step 4: Identify the Product The product of the reaction, sodium borohydride (NaBH4), is a tetrahedral compound and is widely used as a reducing agent in organic synthesis. ### Step 5: Summarize the Compounds - Compound 'A' (the solvent) is diethyl ether. - Compound 'B' (the product) is sodium borohydride (NaBH4). ### Final Answer The compounds 'A' and 'B' respectively are: - A: Diethyl ether (solvent) - B: Sodium borohydride (NaBH4)
To solve the question, we need to identify the compounds 'A' and 'B' based on the information provided. Here's the step-by-step solution: ### Step 1: Identify the Reactants The question states that an alkali metal hydride, specifically sodium hydride (NaH), reacts with diborane (B2H6). ### Step 2: Determine the Reaction When sodium hydride reacts with diborane, the product formed is sodium borohydride (NaBH4). This is a well-known reaction in inorganic chemistry. ...
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