A mixture of 1-iodoethane and 1-iodopropane is treated with sodium metal and dry ether to carry out Wurtz reaction. Which of the following hydrocarbons will be formed?

Options

A. Propane+Hexane
B. Ethane+Propane
C. Butane+Propane
D. Butane+Pentane+Hexane

Explanation

To solve the problem regarding the Wurtz reaction of a mixture of 1-iodoethane and 1-iodopropane, we will follow these steps:

### Step 1: Understand the Wurtz Reaction
The Wurtz reaction involves the coupling of alkyl halides in the presence of sodium metal and dry ether. This reaction typically results in the formation of higher alkanes by combining two alkyl groups.

**Hint:** Remember that the Wurtz reaction uses sodium to generate free radicals from alkyl halides.

### Step 2: Identify the Reactants
In this case, we have two reactants:
- 1-iodoethane (C2H5I)
- 1-iodopropane (C3H7I)

**Hint:** Write down the structures of the reactants to visualize the possible combinations.

### Step 3: Determine the Possible Free Radicals
When 1-iodoethane and 1-iodopropane react with sodium, they will form free radicals:
- From 1-iodoethane: C2H5· (ethyl radical)
- From 1-iodopropane: C3H7· (propyl radical)

**Hint:** Free radicals are highly reactive and can combine in different ways.

### Step 4: Combine the Free Radicals
The free radicals can combine in three possible ways:
1. **Ethyl + Ethyl**:
- C2H5· + C2H5· → C4H10 (butane)

2. **Propyl + Propyl**:
- C3H7· + C3H7· → C6H14 (hexane)

3. **Ethyl + Propyl**:
- C2H5· + C3H7· → C5H12 (pentane)

**Hint:** Consider all combinations of the free radicals to find the products.

### Step 5: List the Products Formed
From the combinations, the products formed are:
- Butane (C4H10)
- Pentane (C5H12)
- Hexane (C6H14)

**Hint:** Ensure that you account for all possible combinations of the free radicals.

### Conclusion
The hydrocarbons that will be formed from the Wurtz reaction of 1-iodoethane and 1-iodopropane are butane, pentane, and hexane.

**Final Answer:** Butane (C4H10), Pentane (C5H12), and Hexane (C6H14).