An alekene X is obtained by dehydration of ann alcohol Y. X on ozonolysis gives two molecules of ethanal for every molecule of alkene. X and Y are

Options

A. X=3-hexene,Y=3-hexanol
B. X=2-butene, Y=2-butanol
C. X=1-butene, Y=1-butanol
D. X=1-hexane, Y=1-hexanol

Explanation

To solve the problem, we need to identify the alkene (X) and the alcohol (Y) based on the given information. Let's break it down step by step.

### Step 1: Identify the Alkene (X)
The problem states that alkene X is obtained by the dehydration of an alcohol Y. Additionally, X undergoes ozonolysis to yield two molecules of ethanal (acetaldehyde) for every molecule of alkene.

### Step 2: Understand Ozonolysis
Ozonolysis is a reaction in which alkenes react with ozone (O3) to form carbonyl compounds (aldehydes or ketones). The ozonolysis of an alkene results in the cleavage of the double bond and the formation of two carbonyl compounds.

### Step 3: Analyze the Product of Ozonolysis
Since ozonolysis of alkene X gives two molecules of ethanal (C2H4O), we can deduce that the structure of X must allow for the formation of two carbonyl groups, each containing two carbons. This indicates that X must be a symmetrical alkene that can be cleaved to yield two identical aldehyde molecules.

### Step 4: Determine the Structure of Alkene X
The simplest symmetrical alkene that can produce two molecules of ethanal upon ozonolysis is 2-butene (C4H8). The ozonolysis of 2-butene would yield two molecules of ethanal:

\[ \text{CH}_3\text{CH}=\text{CHCH}_3 \xrightarrow{O_3} 2 \text{CH}_3\text{CHO} \]

### Step 5: Identify the Alcohol (Y)
Now, we need to find the alcohol Y that can dehydrate to form 2-butene. The alcohol that can be dehydrated to form 2-butene is 2-butanol (C4H10O). The dehydration of 2-butanol in the presence of a dehydrating agent (like dilute H2SO4) leads to the formation of 2-butene.

### Conclusion
Thus, the alkene X is 2-butene, and the alcohol Y is 2-butanol.

### Final Answer:
- Alkene (X): 2-butene (C4H8)
- Alcohol (Y): 2-butanol (C4H10O)

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