An alkene 3-ethylpent-2-ene will give which of the following products on ozonolysis?

Options

A. `HCHO+CH_(3)CH_(2)CH_(2)CHO`
B.
C.
D. `CH_(3)CH_(2)CHO+CH_(3)CH_(2)CH_(2)CH_(2)CHO`

Explanation

To determine the products of ozonolysis for the alkene 3-ethylpent-2-ene, we will follow these steps:

### Step 1: Identify the Structure of the Alkene
The alkene given is 3-ethylpent-2-ene. This means:
- The longest carbon chain has 5 carbon atoms (pent).
- There is a double bond between the second and third carbon atoms (pent-2-ene).
- An ethyl group (C2H5) is attached to the third carbon.

The structure can be drawn as follows:
```
CH2CH3
|
CH3-CH-CH=CH-CH3
```

### Step 2: Understand Ozonolysis
Ozonolysis is a reaction where an alkene reacts with ozone (O3) to form an ozonide intermediate, which is then typically reduced by zinc (Zn) to yield carbonyl compounds (aldehydes or ketones).

### Step 3: Form the Ozonide Intermediate
When 3-ethylpent-2-ene undergoes ozonolysis, it forms an unstable 5-membered ring (ozonide) as an intermediate:
```
O
/ \
CH3-CH-CH-CH-CH3
\ /
O
```

### Step 4: Break the Ozonide
The unstable ozonide will break down to form carbonyl compounds. The double bond between the second and third carbon will cleave, resulting in:
- An aldehyde from the carbon chain that was part of the double bond.
- A ketone from the other part of the carbon chain.

### Step 5: Identify the Products
From the breakdown of the ozonide:
1. The aldehyde formed will be from the terminal carbon (C1) and the carbon (C2) that was part of the double bond:
- **Aldehyde**: CH3C(=O)H (which is propanal)

2. The ketone formed will be from the carbon chain that includes the ethyl group (C3 and C4):
- **Ketone**: CH3CH2C(=O)CH2CH3 (which is 2-pentanone)

### Final Products
Thus, the products of ozonolysis of 3-ethylpent-2-ene are:
- Propanal (an aldehyde)
- 2-pentanone (a ketone)

### Conclusion
The correct answer to the question is that 3-ethylpent-2-ene will yield propanal and 2-pentanone upon ozonolysis.

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