An organic compound `C_(6)H_(12)(X)` on reduction gives `C_(6)H_(14)(Y)`. X on ozonolysis gives two aldehydes `C_(2)H_(4)O(I) and C_(4)H_(8)O(II)`. Identify the compounds X, Y and aldehydes (I) and (II).

Options

A. `X=CH_(3)CH=CHCH_(2)CH_(2)CH_(3),Y=CH_(3)(CH_(2))_(4)CH_(3),(I)=CH_(3)CHO,(II)=CH_(3)(CH_(2))_(2)CHO`
B. `X=CH_(3)CH_(2)CH=CHCH_(2)CH_(3),Y=CH_(3)(CH_(2))_(4)CH_(3),(I)=CH_(3)CHO,(II)=CH_(3)CHO`
C. `X=CH_(3)CH_(2)CH_(2)CH=CH_(2),Y=CH_(3)(CH_(2))_(4)CH_(3),(I)=HCHO,(II)=CH_(3)(CH_(2))_(2)CHO`
D. `X=CH_(3)(CH_(2))_(3)CH_(3),(I)=CH_(3)CHO,(II)=CH_(3)CH_(2)CHO`

Explanation

To solve the problem, we need to identify the organic compound \( C_6H_{12} \) (X), the product of its reduction \( C_6H_{14} \) (Y), and the two aldehydes produced from ozonolysis.

### Step 1: Identify Compound X
Given that the molecular formula of compound X is \( C_6H_{12} \), we can determine its structure. The formula follows the general formula for alkenes \( C_nH_{2n} \), indicating that it is an alkene with one double bond.

To confirm the presence of one double bond, we can use the formula for double bond equivalence (DBE):
\[ \text{DBE} = \frac{C - H + 2}{2} \]
For \( C_6H_{12} \):
\[ \text{DBE} = \frac{6 - 12 + 2}{2} = \frac{-4}{2} + 1 = 1 \]
This confirms that there is one double bond.

### Step 2: Determine Compound Y
When compound X is reduced, it yields \( C_6H_{14} \) (Y). The reduction of an alkene involves the addition of hydrogen (H2), converting the double bond into a single bond, resulting in an alkane.

The alkane \( C_6H_{14} \) is known as hexane. Therefore, we can conclude:
- \( Y = C_6H_{14} \) (Hexane)

### Step 3: Ozonolysis of Compound X
Next, we analyze the ozonolysis of compound X, which produces two aldehydes: \( C_2H_4O \) (I) and \( C_4H_8O \) (II).

Since ozonolysis cleaves the double bond and forms carbonyl compounds, we can deduce the possible structures of the aldehydes:
1. The aldehyde \( C_2H_4O \) corresponds to ethanol (acetaldehyde).
2. The aldehyde \( C_4H_8O \) corresponds to butanal.

### Step 4: Identify Compound X
Given that the ozonolysis of X produces acetaldehyde and butanal, we can deduce the structure of X. The only alkene that fits this ozonolysis pattern is 2-hexene:
\[ \text{Structure of X: } CH_3CH=CHCH_2CH_2CH_3 \]

### Conclusion
Thus, we have identified:
- Compound X: 2-hexene \( (C_6H_{12}) \)
- Compound Y: Hexane \( (C_6H_{14}) \)
- Aldehyde I: Acetaldehyde \( (C_2H_4O) \)
- Aldehyde II: Butanal \( (C_4H_8O) \)

### Final Answer
- X: 2-hexene
- Y: Hexane
- Aldehyde I: Acetaldehyde
- Aldehyde II: Butanal