When 1-butyne undergoes oxymercuraction with the help of `HgSO_(4)+H_(2)SO_(4)`, the product(s) formed is/are

Options

A. `CH_(3)CH_(2)COOH+HCOOH`
B. `CH_(3)CH_(2)COCH_(3)`
C. `CH_(3)CH_(2)CH_(2)COOH`
D. `CH_(3)CH_(2)CH_(2)CHO`

Explanation

To solve the question regarding the product formed when 1-butyne undergoes oxymercuration with the help of HgSO₄ and H₂SO₄, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Structure of 1-Butyne**:
- The structure of 1-butyne is CH₃-CH₂-C≡C-H. It is an alkyne with a triple bond between the last two carbon atoms.

2. **Understanding Oxymercuration**:
- Oxymercuration involves the addition of mercuric ion (Hg²⁺) and water (from H₂SO₄) across the triple bond of the alkyne. The reaction will lead to the formation of an intermediate.

3. **Formation of the Mercurinium Ion**:
- The triple bond of 1-butyne donates its electrons to the mercuric ion (Hg²⁺), forming a mercurinium ion. The structure of this intermediate can be represented as:
- CH₃-CH₂-C(Hg)-C⁺
- Here, the mercuric ion is bonded to one of the carbon atoms of the former triple bond.

4. **Nucleophilic Attack by Water**:
- Water (H₂O) acts as a nucleophile and attacks the more substituted carbon of the mercurinium ion. This leads to the formation of an alcohol intermediate:
- CH₃-CH₂-C(OH)-C(Hg)

5. **Tautomerization**:
- The alcohol intermediate can undergo keto-enol tautomerism. The hydroxyl group (OH) can shift to form a carbonyl group (C=O), resulting in a ketone:
- CH₃-CH₂-C(=O)-CH₃ (butan-2-one)

6. **Final Product**:
- The final product of the reaction is butan-2-one (also known as methyl ethyl ketone).

### Conclusion:
The product formed when 1-butyne undergoes oxymercuration with HgSO₄ and H₂SO₄ is butan-2-one.