the ozonolysis product(s) of the following reaction is(are) `CH_(3)CH_(2)-C-=CH underset("(ii) "H_(2)O)overset((i)" "O_(3))to`product(s)

Options

A. `CH_(3)COCH_(3)`
B. `CH_(3)COCH_(3)+HCHO`
C. `CH_(3)COOH+HCOOH`
D. `CH_(3)CH_(2)COOH+HCOOH`

Answer

To determine the ozonolysis products of the compound \( CH_3CH_2C \equiv CH \) (1-butyne), we will follow these steps:

### Step 1: Ozonolysis Reaction
The first step in ozonolysis is the reaction of the alkyne with ozone (\( O_3 \)). The alkyne will react with ozone to form an unstable ozonide intermediate.

**Reaction:**
\[ CH_3CH_2C \equiv CH + O_3 \rightarrow \text{Ozonide (unstable)} \]

### Step 2: Formation of Ozonide
The ozonide is formed by the addition of ozone to the triple bond. The structure of the ozonide can be represented as follows:

**Ozonide Structure:**
\[ CH_3CH_2C(O)OCH \]

### Step 3: Hydrolysis of Ozonide
The ozonide is then hydrolyzed in the presence of water (\( H_2O \)). This step involves breaking the ozonide to yield carbonyl compounds.

**Hydrolysis Reaction:**
\[ \text{Ozonide} + H_2O \rightarrow \text{Carbonyl compounds} \]

### Step 4: Identify the Products
Upon hydrolysis, the ozonide will yield two carbonyl compounds. In this case, we will get:

1. Propan-2-one (acetone) from the terminal alkyne.
2. Methanoic acid (formic acid) from the other side of the molecule.

**Final Products:**
- Methanoic acid (\( HCOOH \))
- Propan-2-one (\( CH_3COCH_3 \))

### Summary of Products
The ozonolysis of \( CH_3CH_2C \equiv CH \) gives:
- Methanoic acid (formic acid)
- Propan-2-one (acetone)