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The following reaction is known as C(6...

The following reaction is known as
`C_(6)H_(6)+CH_(3)Cl underset(("anhy."))overset(AlCl_(3))to C_(6)H_(5)CH_(3)+HCl`

A

Wurtz-Fittig reaction

B

Friedel-Crafts reaction

C

Rosenmund reaction

D

Sandmeyer reaction

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The correct Answer is:
To solve the question regarding the reaction of benzene with methyl chloride in the presence of anhydrous aluminum chloride, we will break down the process step by step. ### Step-by-Step Solution: 1. **Identify the Reactants and Products:** - The reactants are benzene (C₆H₆) and methyl chloride (CH₃Cl). - The product of the reaction is toluene (C₆H₅CH₃) and hydrochloric acid (HCl). 2. **Recognize the Reaction Type:** - This reaction is an example of an electrophilic aromatic substitution. In this process, an electrophile replaces one of the hydrogen atoms on the benzene ring. 3. **Formation of the Electrophile:** - In the presence of anhydrous aluminum chloride (AlCl₃), methyl chloride (CH₃Cl) reacts to form a methyl cation (CH₃⁺) and a complex ion (AlCl₄⁻). - The reaction can be represented as: \[ CH₃Cl + AlCl₃ \rightarrow CH₃^+ + AlCl₄^- \] 4. **Electrophilic Attack on Benzene:** - The methyl cation (CH₃⁺) acts as an electrophile and attacks the benzene ring. - This leads to the formation of a sigma complex (also known as an arenium ion), where a hydrogen atom is temporarily removed from the benzene ring. - The reaction can be illustrated as: \[ C₆H₆ + CH₃^+ \rightarrow C₆H₅CH₃^+ \text{ (sigma complex)} \] 5. **Rearrangement and Restoration of Aromaticity:** - The sigma complex is not aromatic and is less stable. To regain aromaticity, it loses a proton (H⁺). - This step restores the aromatic character of the benzene ring and forms toluene (C₆H₅CH₃). - The reaction can be summarized as: \[ C₆H₅CH₃^+ \rightarrow C₆H₅CH₃ + H^+ \] 6. **Formation of HCl:** - The proton (H⁺) that is released combines with AlCl₄⁻ to regenerate AlCl₃ and produce hydrochloric acid (HCl): \[ H^+ + AlCl₄^- \rightarrow AlCl₃ + HCl \] 7. **Final Reaction Summary:** - The overall reaction can be summarized as: \[ C₆H₆ + CH₃Cl \xrightarrow{AlCl₃} C₆H₅CH₃ + HCl \] 8. **Naming the Reaction:** - This reaction is known as the **Friedel-Crafts Alkylation**. ### Conclusion: The reaction of benzene with methyl chloride in the presence of anhydrous aluminum chloride is called **Friedel-Crafts Alkylation**.

To solve the question regarding the reaction of benzene with methyl chloride in the presence of anhydrous aluminum chloride, we will break down the process step by step. ### Step-by-Step Solution: 1. **Identify the Reactants and Products:** - The reactants are benzene (C₆H₆) and methyl chloride (CH₃Cl). - The product of the reaction is toluene (C₆H₅CH₃) and hydrochloric acid (HCl). ...
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NCERT FINGERTIPS ENGLISH-HYDROCARBONS -Assertion And Reason
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  7. Assertion: Iodination of alkanes is carried out in the presence of oxi...

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  9. Assertion: cis-form of alkene is found to be more polar than the trans...

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  12. Assertion: Decolourisation of KMnO(4) solution is used as a test for u...

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  14. Assertion: Cyclopentadienyl anion is aromatic in nature. Reason: Cyc...

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