The reduction of benzoyl chloride with `H_(2)//Pd-BaSO_(4)` produces

Options

A. benzoic acid
B. benzyl alcohol
C. benzoyl sulphate
D. benzaldehyde.

Answer

To solve the question regarding the reduction of benzoyl chloride with `H2` in the presence of `Pd-BaSO4`, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactant**:
- The reactant is benzoyl chloride, which has the structure C6H5C(O)Cl. This compound consists of a benzene ring (C6H5) attached to a carbonyl group (C=O) and a chlorine atom (Cl).

2. **Understand the Reduction Process**:
- The reduction of benzoyl chloride involves the addition of hydrogen (H2) to the carbonyl group (C=O) and the replacement of the chlorine atom (Cl) with a hydrogen atom (H).

3. **Identify the Catalyst**:
- The catalyst used in this reaction is palladium (Pd) supported on barium sulfate (BaSO4). This combination is specifically used to control the reaction and prevent over-reduction.

4. **Recognize the Type of Reaction**:
- This reaction is known as Rosenmund reduction. It is a selective reduction process where acyl chlorides are converted to aldehydes without further reducing them to alcohols.

5. **Write the Reaction**:
- The reaction can be summarized as:
\[ \text{C6H5C(O)Cl} + \text{H2} \xrightarrow{\text{Pd-BaSO4}} \text{C6H5CHO} + \text{HCl} \]
- Here, benzoyl chloride is reduced to benzaldehyde (C6H5CHO), and hydrochloric acid (HCl) is produced as a byproduct.

6. **Identify the Product**:
- The product of this reaction is benzaldehyde, which is an aromatic aldehyde.

### Final Answer:
The reduction of benzoyl chloride with `H2` in the presence of `Pd-BaSO4` produces **benzaldehyde (C6H5CHO)**.