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Complete the missing lnks (X), (Y) and (...

Complete the missing lnks (X), (Y) and (Z) by making an appropriate choice.
`CH_(3)COOH overset(PBr_(3)//Br_(2))toXoverset(KCN)toYoverset(H_(3)O^(+))toZ`

A

`{:(" X"," Y"," Z"),(CH_(3)COBr,CH_(3)COCN,CH_(3)COOH):}`

B

`{:(" X"," Y"," Z"),(BrCH_(2)COOH,underset(CN)underset(|)CH_(2)COOH,HOOC-CH_(2)COOH):}`

C

`{:(" X"," Y"," Z"),(BrCH_(2)COOH,CH_(2)(CN)COOH,overset(" COOH")underset(" COOH")("|")):}`

D

`{:(" X"," Y"," Z"),(Br_(2)CHCOOH,Br_(2)C(CN)COOH,CH_(3)CH_(2)COOH):}`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we need to identify the compounds X, Y, and Z in the reaction sequence starting from acetic acid (CH₃COOH) and going through the given reagents. ### Step-by-Step Solution: 1. **Identify the starting compound:** The starting compound is acetic acid, which has the structure CH₃COOH. 2. **Reaction with PBr₃ and Br₂:** Acetic acid reacts with phosphorus tribromide (PBr₃) and bromine (Br₂). This reaction will convert the hydroxyl (-OH) group of acetic acid into a bromine atom, resulting in the formation of brominated acetic acid. - **Product X:** The product formed is brominated acetic acid, which can be represented as BrCH₂COOH. 3. **Reaction with KCN:** The brominated acetic acid (X) then reacts with potassium cyanide (KCN). In this step, the cyanide ion (CN⁻) acts as a nucleophile and attacks the carbon atom bonded to the bromine atom, leading to the substitution of the bromine atom with the cyanide group. - **Product Y:** The product formed is 2-cyanoacetic acid, which can be represented as CNCH₂COOH. 4. **Reaction with H₃O⁺:** The 2-cyanoacetic acid (Y) then undergoes acidic hydrolysis when treated with hydronium ions (H₃O⁺). During this reaction, the cyano group (CN) is converted into a carboxylic acid group (-COOH) through hydrolysis. - **Product Z:** The final product formed is 2-carboxyacetic acid, which can be represented as HOOC-CH₂-COOH. ### Summary of Products: - **X:** BrCH₂COOH (Brominated acetic acid) - **Y:** CNCH₂COOH (2-Cyanoacetic acid) - **Z:** HOOC-CH₂-COOH (2-Carboxyacetic acid) Thus, the missing links are: - (X) = BrCH₂COOH - (Y) = CNCH₂COOH - (Z) = HOOC-CH₂-COOH

To solve the question, we need to identify the compounds X, Y, and Z in the reaction sequence starting from acetic acid (CH₃COOH) and going through the given reagents. ### Step-by-Step Solution: 1. **Identify the starting compound:** The starting compound is acetic acid, which has the structure CH₃COOH. 2. **Reaction with PBr₃ and Br₂:** ...
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NCERT FINGERTIPS ENGLISH-ALDEHYDES, KETONES AND CARBOXYLIC ACIDS-MCQs(CHEMICAL REACTIONS )
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  7. Identify (X), (Y) andc (Z) in the given reaction : CH(3)CHO overset(...

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  8. Complete the missing lnks (X), (Y) and (Z) by making an appropriate c...

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  9. What happens when a carboxylic acid is treated with lithium aluminum h...

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  12. Fill in the blanks. In Hell-Volhard-Zelinsky reaction, the carboxyli...

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