A compound (X) having molecualr formula `C_(4)H_(8)O_(2)` is hydrolysed by water in presence of an acid to give a carboxylic acid (Y) and an alcohol (Z). (Z) on oxidation with chromic acid gives (Y), (X), (Y) and (Z) are

Options

A. `{:(" X"," Y"," Z"),(CH_(3)COOCH_(3),CH_(3)COOH,CH_(3)OH):}`
B. `{:(" X"," Y"," Z"),(CH_(3)COOC_(2)H_(5),CH_(3)COOH,C_(2)H_(5)OH):}`
C. `{:(" X"," Y"," Z"),(C_(2)H_(5)COOCH_(3),C_(2)H_(5)COOH,C_(2)H_(5)OH):}`
D. `{:(" X"," Y"," Z"),(CH_(3)COOC_(2)H_(5),C_(2)H_(5)COOH,CH_(3)OH):}`

Explanation

To solve the problem step by step, we need to identify the compound (X) with the molecular formula \( C_4H_8O_2 \) and determine the carboxylic acid (Y) and alcohol (Z) produced from its hydrolysis.

### Step 1: Identify Compound X
The molecular formula of compound (X) is \( C_4H_8O_2 \). This formula suggests that (X) could be an ester, as esters typically have the general formula \( RCOOR' \) where \( R \) and \( R' \) are hydrocarbon chains.

### Step 2: Propose a Structure for X
Let's consider a possible structure for (X):
- One possible structure is Ethyl acetate, which can be represented as:
\[ CH_3COOCH_2CH_3 \]
This structure has:
- 4 Carbon atoms
- 8 Hydrogen atoms
- 2 Oxygen atoms

### Step 3: Hydrolysis of X
When (X) is hydrolyzed in the presence of water and an acid, it breaks down into a carboxylic acid (Y) and an alcohol (Z). The hydrolysis of ethyl acetate can be represented as:
\[ CH_3COOCH_2CH_3 + H_2O \rightarrow CH_3COOH + CH_3CH_2OH \]
Here:
- (Y) is Acetic acid (\( CH_3COOH \))
- (Z) is Ethanol (\( CH_3CH_2OH \))

### Step 4: Oxidation of Z
Next, we need to check the oxidation of (Z) with chromic acid. Ethanol (\( CH_3CH_2OH \)) is oxidized to acetic acid (\( CH_3COOH \)):
\[ CH_3CH_2OH + [O] \rightarrow CH_3COOH \]
This confirms that (Z) oxidizes to give (Y).

### Conclusion
Thus, we can summarize:
- Compound (X) is Ethyl acetate (\( CH_3COOCH_2CH_3 \))
- Carboxylic acid (Y) is Acetic acid (\( CH_3COOH \))
- Alcohol (Z) is Ethanol (\( CH_3CH_2OH \))

### Final Answer:
- \( X = \text{Ethyl acetate} \)
- \( Y = \text{Acetic acid} \)
- \( Z = \text{Ethanol} \)