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The oxidation of central atom in the com...

The oxidation of central atom in the complex ` [ Co(NH_(3))_(4) CINO_(2)]` is

A

` +2`

B

`+3`

C

`+1`

D

zero

Text Solution

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The correct Answer is:
To determine the oxidation state of the central atom (cobalt) in the complex \([Co(NH_3)_4ClNO_2]\), we can follow these steps: ### Step 1: Identify the ligands and their charges - The complex contains: - 4 ammonia (NH₃) ligands, which are neutral (charge = 0). - 1 chloro (Cl) ligand, which has a charge of -1. - 1 nitro (NO₂) ligand, which typically has a charge of -1. ### Step 2: Set up the equation for the oxidation state Let the oxidation state of cobalt be \(X\). The overall charge of the complex is neutral (0), so we can set up the equation as follows: \[ X + (4 \times 0) + (-1) + (-1) = 0 \] ### Step 3: Simplify the equation This simplifies to: \[ X - 2 = 0 \] ### Step 4: Solve for \(X\) Now, we can solve for \(X\): \[ X = 2 \] ### Conclusion The oxidation state of cobalt in the complex \([Co(NH_3)_4ClNO_2]\) is \(+2\).
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Knowledge Check

  • The oxidation state of central atom in the anion of compound NaH_(2)PO_(2) will be . . . . . . . . .

    A
    `+3`
    B
    `+5`
    C
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  • The coordination number (C.N.) and oxidation number (O.N.) of central metal atom in the complex K_3[Fe(CN)_6] is :

    A
    C.N. = 3, O.N. = +3
    B
    C.N. = 6, O.N. = +6
    C
    CN. =6, ON =+3
    D
    CN. =3, ON. =+6.
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