When acyl chloride is heated with Na Salt of a carboxylic acid the product is

Options

A. an aldehyde
B. an alkene
C. an anhydride
D. an ester.

Answer

To solve the question, we need to analyze the reaction between acyl chloride and the sodium salt of a carboxylic acid. Here’s a step-by-step solution:

### Step 1: Identify the Reactants
We start with two reactants:
1. **Acyl Chloride**: This can be represented as RCOCl, where R is an alkyl or aryl group.
2. **Sodium Salt of a Carboxylic Acid**: This can be represented as R'COONa, where R' is another alkyl or aryl group.

### Step 2: Understand the Reaction Mechanism
When the acyl chloride (RCOCl) is heated with the sodium salt of a carboxylic acid (R'COONa), the negatively charged oxygen from the carboxylate ion (R'COO-) will attack the electrophilic carbon of the acyl chloride.

### Step 3: Nucleophilic Attack
The nucleophilic oxygen (from R'COO-) attacks the carbon atom of the acyl chloride (RCOCl). This results in the formation of a tetrahedral intermediate.

### Step 4: Elimination of Leaving Groups
As the tetrahedral intermediate forms, the chloride ion (Cl-) leaves, and the sodium ion (Na+) from the sodium salt also dissociates. This leads to the formation of a new bond between the acyl group and the carboxylate group.

### Step 5: Formation of the Product
The product formed from this reaction is an **anhydride**. The general structure of the product can be represented as RCOOR', where RCO- is derived from the acyl chloride, and R'CO- is derived from the sodium salt of the carboxylic acid.

### Step 6: By-products
The by-product of this reaction is sodium chloride (NaCl), which is formed from the sodium ion and the chloride ion that were released during the reaction.

### Final Product
Thus, the final product of the reaction between acyl chloride and the sodium salt of a carboxylic acid is an **anhydride**.

### Conclusion
The correct answer to the question is that the product formed is an **anhydride**.

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