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The correct order of equivalent conduct...

The correct order of equivalent conductance at infinite dilution of LiCI, NaCI and KCI is

A

LiCI gt NaCI gt KCI

B

KCI gt NaCI gt LiCI

C

NaCI gt KCI gt LiCI

D

LiCI gt KCI gt NaCI

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The correct Answer is:
To determine the correct order of equivalent conductance at infinite dilution of LiCl, NaCl, and KCl, we need to analyze the factors affecting ionic conductance. ### Step-by-Step Solution: 1. **Understanding Equivalent Conductance**: Equivalent conductance (Λ) at infinite dilution refers to the conductance of all ions in solution when they are completely separated. It is influenced by the mobility of the ions. 2. **Analyzing the Cations**: The compounds in question (LiCl, NaCl, KCl) all have the same anion (Cl⁻) but different cations (Li⁺, Na⁺, K⁺). The charge on these cations is the same (+1), but their sizes differ. 3. **Ionic Size and Hydration**: As we move down the alkali metal group in the periodic table from Li to Na to K, the ionic radius increases. This means: - Li⁺ < Na⁺ < K⁺ (in terms of size). - Smaller cations (like Li⁺) have a higher degree of hydration because they can attract water molecules more strongly due to their higher charge density. 4. **Degree of Solvation**: The degree of solvation decreases as the size of the cation increases. Therefore: - Li⁺ is heavily hydrated, leading to a larger hydrated radius. - Na⁺ is moderately hydrated. - K⁺ is the least hydrated. 5. **Ionic Mobility**: The mobility of ions in solution is inversely related to their hydrated size. Smaller hydrated ions move more freely: - Li⁺ has a larger hydrated radius and thus lower mobility. - Na⁺ has moderate mobility. - K⁺, being the largest, has the smallest hydrated radius and therefore the highest mobility. 6. **Conductance Order**: Since the mobility of the ions is highest for K⁺, followed by Na⁺, and lowest for Li⁺, we can conclude: - KCl > NaCl > LiCl in terms of equivalent conductance at infinite dilution. ### Final Order: The correct order of equivalent conductance at infinite dilution is: **KCl > NaCl > LiCl**
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