If `f(x)= [x], g (x) = abs(x)`, then find the value of `(fog) (5/2) - (gof)(-5/2)`

Let f(x) = [x] and g(x) = |x| then find the value of (fog)(1/2) - (gof) (1/2)

Let f(x) = [x] and g(x) = |x| then find the value of (gof) (5/3) - (fog) (5/3)

If f : R rarr R and g : R rarr R be two mapping such that f(x) = sin x and g(x) = x^(2) , then find the values of (fog) (sqrt(pi))/(2) "and (gof)"((pi)/(3)) .

If f (x)= x^2 and g (x) =2x + 3 , then the value of gof(-1) is:

If f(x) = x^2 and g (x) = 2x + 3 , then the value of gof (-1) is

If f:R -> R, g:R -> R defined as f(x) = sin x and g(x) = x^2 , then find the value of (gof)(x) and (fog)(x) and also prove that gof != fog .

If f (x) = [x] and g (x) = I x I , then evaluate : (fog) (frac{1}{2})- (gof)(frac{-1}{2})

Let f(x) = [x] and g(x) = |x| find (fog)(5/2) -(gof) ((-5)/2)

If f(x) = sqrtx and g(x) = 2x -3 , then domain of (fog) (x) is