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If f(x) ={(kx^2),(3):}, ((x <3),(x ge3))...

If `f(x) ={(kx^2),(3):}, ((x <3),(x ge3))` and f is continuous at x = 3 then value of k is :

A

`1/3`

B

`1/9`

C

`3/7`

D

`7/3`

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