Find the equation of normal to the curve, `y = .x^3` at the point (-1.-1).

Find the equation of normal to the curve, y = .x^3 at the point (2,8).

Find the equation of the normal to the curve y = x^3 at the point (2,1).

Find the equation of the normal to curve y^2=4x at the point (1,2)

Find the slope of the normal to the curve y = 1/x at the point (1/3,3)

Find the slope of the normal to the curve y = x^3-xat x = 2

The slope of normal to the curve y = x^2 +3 at x=1 is

Find the slope of the normal to the curve y=x^3-x+1 at the point whose x- coordinate is 2.

Find the equation of normal to the curve : y = x^3 + x^2 - 11x + 15 , where normal is parallel to the line x - 3y + 1 = 0

Find the equation of normal to the curve y = x^3 - 7x^2 -20x + 1 where normal is parallel to the line x + 4y + 7 = 0 .