Area bounded by the ellipse : x^2/16 + y...

Area bounded by the ellipse : `x^2/16 + y^2/9 = 1` is :

A

`9 pi` Sq. units

B

`16 pi` sq. unit

C

`12 pi` Sq. units

D

None of these

Verified by Experts

|

Similar Questions

Explore conceptually related problems

Using integration, find the area bounded by the ellipse : x^2/9 + y^2/4 = 1 .

Using integration find the area of region bounded by the ellipse x^2/16 + y^2/9 = 1

Using integration find the area of region bounded by the ellipse x^2/16 + y^2/25 = 1

Find the area of region bounded by the ellipse x^2/4 + y^2/9 = 1

Find the area bounded by the ellipse x^(2)/16+y^(2)/9=1

Find the area bounded by the ellipse x^2/a^2 + y^2/b^2 = 1 and the ordinates x=0 and x=ae , where b^2 = a^2 (1-e^2) and e<1 .

Using integration find the area bounded by the ellipse x^(2)/16+y^(2)/25=1 .

Find the area of the region bounded by the ellipse (x^(2))/(16) + (y^(2))/(9) = 1 .

Find the area of the region bounded by the ellipse x^(2)/16+y^(2)/9=1 .

Using integration find the area of region bounded by the ellipse x^2/25 + y^2/16 = 1