Find the flux density of the magnetic field to cause 62.5eV electron to move in a circular path of the radius 5cm. Given`m = 9.1xx10^(-31)`,kg, e = `1.6xx10^(-19)C`

Find the flux density of the magnetic field to cause 62.5 eV electron to move in a circular path of radius 5 cm. Given m = 9.1 xx 10^-31 kg, e = 1.6 xx 10^-19 C

An electron after bein accelerated through a potential difference of 1 00 V enters a uniform magnetic field of 0.004 T perpendiular to its direction of motion. Calculate the radius of the path describe by the electron. Given m = 9.1 xx 10^-31 kg and e = 1.6 xx 10^-19 C

Calculate the strength of magnetic field due to an electron revolving in a circle of radius 2xx10^-10 m with a speed of 5xx10^6 ms^-1 at its centre.

Calculate the ratio of electrostatic to gravitational force between two electrons placed at a certain distance in air. Given that m_e = 9.1 xx 10^31 kg, e = 1.6 xx 10^19C and G = 6.6 xx 10^17 N m^2 kg^-2

Calculate the radius of the third orbit of the electron in hydrogen atom.Given that Planck's constant, h=6.62 xx 10^(-34) J s,m=9.1 xx 10^(-31) kg,e=1=1.6 xx 10^(-19)C .

If the free electron density of copper is 8.6xx10^(28)m^(-3) and resistivity of copper at room temperature is 1.7xx10^(-6)Omega cm , find the relaxation time for the free electrons of copper. Given, mass of electron =9.1xx10^(-31) kg , and charge of electron =1.6xx10^(-19)C. Boltzmann's constant k = 1.38 xx 10^-23 J K^-1