Considering the circuit and data given in the diagram calculate the currents flowing in the diodes `D_(1)` and `D_(2)` with linear characteristics.Forward resistance of `D_(1)` and `D_(2)` is 20 `Omega`

Explanation

Since the positive of bettery is connected to P-type both diodes `D_(1)` and `D_(2)` are forward biased .Hence they may be replaced by short (closed ) switch associated with their forward resistance as shown in Fig.

The resistance of `20Omega` and `20Omega` in parallel
`(1)/(R)=(1)/(20)+(1)/(20)=(2)/(20)` (or) `R=(20)/(2)=10 Omega`
Therefore ,total current 1 in the circuit
`I=(1)/(100+10)=(1)/(110)` amp and
`I_(1)=I_(2)=(1)/(2)xx(1)/(110)=(1)/(220)amp`