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Current amplification factor of a common...

Current amplification factor of a common base configuration is 0.88. Find the value of base current when the emitter current is 1 mA.

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In a common-base arrangement, the current amplification factor.
`alpha=((deltaI_(C))/(deltaI_(E)))_(V_(CB))=(I_(C))/(I_(E))`
(if only d.e. value are considered )
Given `alpha`=0.88 ,`I_(E)=1mA`.
`therefore` Collector current
`I_(C)=alphaI_(E)=0.88xx1=0.88mA`
Now since `I_(E)=I_(B)+I_(C)`
`therefore` Base current `I_(B)=I_(E)-I_(C)`
`=1-0.88
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