Two identical capacitors are connected in series. Charge on each capacitor is `q_0`. A dielectric slab is now introduced between the plates of one of the capacitors so as to fill the gap, the battery remaining connected. The charge in each capacitor will now be

Options

A. `(2q_0)/( 1+(1)/(K))`
B. `(q_0)/(1 +(1)/(K))`
C. `(2q_0)/(1+K) `
D. `(q_0)/(1+K)`

Answer

A