The circuit shown below contains two diodes, each of forward resistance, 50 `Omega` and with infinite backward resistance. If the battery voltage is 6V, find the current through 100 `Omega` resistance.

Explanation

As per given circuit, diode `D_1 ` is forward biased and offers a resistance of 50 ohm. Diode `D_2` is reverse biased and as its corresponding resistance circuit is as shown in Fig. As all the three resistances are in series, the current through them is

` I=(6V )/( (50+150 + 100 ) W ) =(6)/(300 )A = 0.02A`