When ‘n’ identical droplets are combined...

When ‘n’ identical droplets are combined to form a big drop, then the energy will be released
Work done to form a big drop from ‘n’ identical droplets each of radius r is

`W= 4 pi r^2 T (n-n^(2//3))`

`W= 2 pi r^2 T (n-n^(2//3))`

`W= 4 pi r^2 T (n-n^(1//3))`

`W= 2 pi r^2 T (n-n^(1//3))`

Verified by Experts

The correct Answer is:

SURFACE TENSION
AAKASH SERIES|Exercise LECTURE SHEET (EXERCISE -I (MATRIX MATCHING TYPE QUESTIONS))|1 Videos
SURFACE TENSION
AAKASH SERIES|Exercise LECTURE SHEET (EXERCISE -I (INTEGER TYPE QUESTIONS ))|4 Videos
SURFACE TENSION
AAKASH SERIES|Exercise LECTURE SHEET (EXERCISE -I (MORE THAN ONE CORRECT ANSWER TYPE QUESTIONS))|2 Videos
SIMPLE HARMONIC MOTION
AAKASH SERIES|Exercise ADDITIONAL PRACTICE EXERCISE (LEVEL - II)(PRACTICE SHEET (ADVANCED)) (INTEGER TYPE QUESTIONS)|3 Videos
SYSTEM OF PARTICLES AND ROTATIONAL MOTION
AAKASH SERIES|Exercise PRACTICE EXERCISE|99 Videos

When ‘n’ identical droplets are combined to form a big drop, then the energy will be released If n identical small droplets each of radius r merge to form a big drop of radius R and the energy released in this process is absorbed by the big drop so as to increase its kinetic energy then the speed of the big drop (T be the surface tension and d be the density of the liquid droplets)

` sqrt((6T )/(d) [(r )/( R ) -(1)/(r )])`

` sqrt((6T )/(d) [(1 )/( r ) -(1)/(R)])`

` sqrt((6d )/(T) [(1 )/( R ) -(1)/(r )])`

` sqrt((6T )/(d) [(1 )/( r ) -(1)/(R )])`

`(3T)/( djS )[(1)/(r ) -(1)/( R )]`

`(3T)/( djS )[(1)/(R ) -(1)/( r )]`

`(3Td)/( JS )[(1)/(R ) -(1)/( r )]`

`(3Td)/( JS )[(1)/(r ) -(1)/( R )]`

`1: 10`

`1:15`

`1:20`

`1:25`