When small droplets floating in atmosphe...

When small droplets floating in atmosphere merge into each other in clouds, they become heavy and cannot float in air and fall down as rain drops. In this process of formation of bigger drops if 'n' small drops each of radius 'r', surface tension “T” coalesce. Then
If P is the excess pressure in a smaller drop, the excess pressure in bigger drop is

`P`

`n^(1//3) P`

`( P)/( n^(1//3))`

`nP`

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The correct Answer is:

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When small droplets floating in atmosphere merge into each other in clouds, they become heavy and cannot float in air and fall down as rain drops. In this process of formation of bigger drops if 'n' small drops each of radius 'r', surface tension “T” coalesce. Then When smaller drops combine energy is released or absorbed, which is given by

Energy released`= 4 pi R^3 ((1)/(R ) - (1)/(r ) )T`

Energy released `= 4 pi R^3 ((1)/(r) - (1)/(R ))T `

Energy absorbed `= 4pi R^3 ((1)/(R ) - (1)/( r ) ) T `

Energy absorbed `= 4pi R^3 ((1)/(r )-(1)/(R )) T`

`146N m^-2`

`126N m^-2`

`256N m^-2`

`746N m^-2`

`W= 4 pi r^2 T (n-n^(2//3))`

`W= 2 pi r^2 T (n-n^(2//3))`

`W= 4 pi r^2 T (n-n^(1//3))`

`W= 2 pi r^2 T (n-n^(1//3))`