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If the work done in blowing a soap bubbl...

If the work done in blowing a soap bubble of volume 'V' is W, then the work done in blowing a soap bubble of volume '2V' is

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Calculate the work done in blowing a soap bubble of diameter 0.6 cm against the surface tension force. (surface tension of soap solution = 2.5xx10^(2) Nm^(-1) ).

Calculate the work done in blowing a soap bubble of diameter 0.6 cm. against the surface tension force. (Surface tension of soap solution =2.5 times 10^-2 Nm^-1 )

Knowledge Check

  • If the work done in blowing a soa bubble of volume 'v' is w, then the work done in blowing a soap bubble of volume '2v' is

    A
    `4W`
    B
    `8W`
    C
    `2^(1//3)W`
    D
    `4^(1//3)W`
  • If the work done in blowing a bubble of volume V is W then the work done in blowing a soap bubble of volume 2V will be:

    A
    W
    B
    2W
    C
    `sqrt(2) W`
    D
    `root(3) (4) W`
  • The work done in blowing a soap bubble of radius 0.2 m is (surface tension of water is 0.06N/m)

    A
    `192pixx10^(-4)J`
    B
    `280pixx10^(-4)J`
    C
    `200pixx10^(-4)J`
    D
    `96pixx10^(-4)J`
  • Similar Questions

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    Calculate the work done in blowing a soap bubble of radius 2 cm. Surface tension of soap solution =7xx10^(-2)Nm^(-1)

    The work done to blow a bubble is W. the extra work to be done to double its radius is

    The workdone in bowing a soap bubble of radius aunder isothermal conditions is (the surface tension of soap film is T)

    The surface tension of soap solution is 0.03 Nm^(-1) . The work done in blowing to form a soap bubble of surface area 40 cm^2 , (in J), is

    The workdone in blowing a spherical soap bubble of diameter 2 cm will be (the surface tension of soap solution is 2xx10^(-2)Nm^(-1) )