A particle executes SHM of time period T. Find time by the particle to go from its mean position to half of the amplitude.

Explanation

Consider the equation of motion, x = `A sin wT ,` At t=0 , x=0 i.e. , at mean position
The particle will be at x = `A/2` , at a time , where `A/2` = `A sin omega t = sin omega t = 1//2` , `sin omega t = sin pi//6`
`omega t = pi/6 ` (or) `(2pi)/(T) t = (pi)/(6) `(or)
`t= T/(12)` , Time taken `T/(12)`