If `cos alpha+ cos beta+ cos gamma=0` and also `sin alpha+ sin beta+ sin gamma= 0`, then prove that

If cos alpha + cos beta + cos gamma = 3 then sin alpha + sin beta + sin gamma =

If cos alpha + 2 cos beta +3 cos gamma = sin alpha + 2 sin beta + 3 sin gamma y = 0 , then the value of sin 3alpha + 8 sin 3beta + 27 sin 3gamma is

If cos alpha + cos beta + cos gamma = 0 = sin alpha + sin beta + sin gamma then cos ^ (2) alpha + cos ^ (2) beta + cos ^ (2) gamma is

If cos alpha + cos beta + cos gamma = 0 = sin alpha + sin beta + sin gamma then (a) sin ^ (2) alpha + sin ^ (2) beta + sin ^ (2) gamma = (3) / ( 2) (b) sin ^ (2) alpha + sin ^ (2) beta + sin ^ (2) gamma = (3) / (4) (c) cos ^ (alpha) + cos ^ (2) beta + cos ^ (2) gamma = (3) / (2) (d) cos ^ (2) alpha + cos2 beta + cos2 gamma = -1

Let A and B denote the statements A : cos alpha + cos beta + cos gamma =0 B : sin alpha + siin beta + sin gamma = 0 If cos(beta - gamma) + cos (gamma -alpha) + cos (alpha -beta) = - (3)/(2) , then

if cos alpha+cos beta+cos gamma=0=sin alpha+sin beta+sin gamma then prove that cos2 alpha+cos2 beta+cos2 gamma=sin2 alpha+sin2 beta+sin2 gamma=0

If cos alpha + cos beta+ cos gamma = 0 = sin alpha + sin beta+sin gamma show that sin^(2)alpha + sin^(2) beta + sin^(2) gamma =cos^(2)alpha +cos^(2) beta + cos^(2) gamma =3/2