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A DAS GUPTA-Limit, Indetermine Form-Exercise
- Fill in the blanks: lim(x rarr oo )(sqrt(x))/(sqrt(x)+sqrt(x)+sqrt(x))...
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- lim(h->0)(log(1+2h)-2log(1+h))/(h^2)=.........
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- Fill in the blanks: lim(x rarr 0) (1+sin x)^(cosec x) .
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- lim(x-gtoo){(x+6)/(x+1)}^(x+4)
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- Fill in the blanks: lim(n rarr oo) ((3x-4)/(3x+2))^((x+1)/3) .
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- ("lim")(xvec0)((1+5x^2)/(1+3x^2))^1//x^2=
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- Fill in the blanks: lim(x rarr oo) ((x^2+1)/(x^2-1))^(x^2)=
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- Lim(x->0) {x(1+acosx)-bsinx}/x^3=1 then
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- If f'(2)=2, f''(2) =1, then lim(xto2)(2x^2-4f'(x))/(x-2), is
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- If f(9)=9 , f'(9)= 4 then lim (x rarr9) (sqrt f(x) -3)/(sqrt(x)-3) =.
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- If G(x)=-sqrt(25-x^2),t h e n("lim")(xvec1)(G(x)-G(1))/(x-1)i s 1/(24...
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- If f(a) =2, f'(a)=1, g(a) =-1 , g' (a)=2, then the value of lim(xto a)...
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- If lim(x rarr a)(px+q)/(qx+p)=l and lim(x rarr0)(px+q)/(qx+p)=m where ...
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- If f(x)=sqrt((x-sinx)/(x+cos^2x)), then lim (x->oo)f(x) is
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- lim(x->0)(x e^x-log(1+x))/(x^2) equals
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- Lim(x->0) {x(1+acosx)-bsinx}/x^3=1 then
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- Let f(x) be a twice-differentiable function and f"(0)=2. The evaluate:...
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- lim (x rarr pi/2) (2x-pi)/cos x is equal to
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- evaluate lim(thetararrpi/4)(sqrt2-costheta-sintheta)/(4theta-pi)^2
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- If f(x)=cot^(-1) ((3x-x^3)/(1-3x^2)) and g(x)=cos^(-1)((1-x^2)/(1+x^2)...
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