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A DAS GUPTA-Limit, Indetermine Form-Exercise
- Lim(x->0) {x(1+acosx)-bsinx}/x^3=1 then
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- If f'(2)=2, f''(2) =1, then lim(xto2)(2x^2-4f'(x))/(x-2), is
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- If f(9)=9 , f'(9)= 4 then lim (x rarr9) (sqrt f(x) -3)/(sqrt(x)-3) =.
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- If G(x)=-sqrt(25-x^2),t h e n("lim")(xvec1)(G(x)-G(1))/(x-1)i s 1/(24...
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- If f(a) =2, f'(a)=1, g(a) =-1 , g' (a)=2, then the value of lim(xto a)...
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- If lim(x rarr a)(px+q)/(qx+p)=l and lim(x rarr0)(px+q)/(qx+p)=m where ...
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- If f(x)=sqrt((x-sinx)/(x+cos^2x)), then lim (x->oo)f(x) is
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- lim(x->0)(x e^x-log(1+x))/(x^2) equals
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- Lim(x->0) {x(1+acosx)-bsinx}/x^3=1 then
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- Let f(x) be a twice-differentiable function and f"(0)=2. The evaluate:...
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- lim (x rarr pi/2) (2x-pi)/cos x is equal to
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- evaluate lim(thetararrpi/4)(sqrt2-costheta-sintheta)/(4theta-pi)^2
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- If f(x)=cot^(-1) ((3x-x^3)/(1-3x^2)) and g(x)=cos^(-1)((1-x^2)/(1+x^2)...
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- 23. The value of lim(h->0)(1/(h(8+h)^(1/3)) - 1/(2h)) equals
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- Evaluate: ("lim")(hvec0)(2[sqrt(3)sin(pi/6+h)-cos(pi/6+h)])/(sqrt(3)h(...
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- lim(x->0)(sqrt((1-cos2x)/2))/x
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- lim(x rarr 0) (log(1+x))/(3^x-1)=1/(log(e)(3))
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- lim(x->a)(cosx-cosa)/(cotx-cota)=
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- lim(x to0) sin x /x =1
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- lim(x rarr 0) x^2/y = 0
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