Prove that,
`tan3A.tan2A.tanA=tan3A-tan2A-tanA`

Show that, tan3xtan2xtanx=tan3x-tan2x-tanx .

Show that tan 3x tan 2x tan x = tan 3x - tan 2x - tan x

The value of tan3A-tan2A-tanA is

By using above basic addition/ subtraction formulae, prove that (i) tan (A+B)=(tan A+tan B)/(1-tan A tan B) , (ii) tan (A-B)=(tan A-tanB)/(1+tan A tan B) (iii) sin2theta=2sintheta costheta , (iv) cos2theta=cos^(2)theta=1-2sin^(2)theta=2cos^(2)theta-1 (v) tan 2theta=(2 tan theta)/(1-tan^(2) theta)

Prove that : tan 20° tan 35° tan 45° tan 55° tan 70° = 1

Prove that : t a n A+tan(60^0+A)+tan(120^0+A)=3t a n3A

Prove that tan4x=(4tanx(1-tan^(2)x))/(1-6tan^(2)x+tan^(4)x)

Prove that tan4x=(4tanx(1-tan^(2)x))/(1-6tan^(2)x+tan^(4)x)

Prove that, tan25^(@).tan15^(@)+tan15^(@)tan50^(@)+tan25^(@)tan50^(@)=1 .

If costheta=(cosalphacosbeta)/(1-sinalphasinbeta) then prove that tan((theta)/(2))=(tan((alpha)/(2))-tan((beta)/(2)))/(1-tan((alpha)/(2))tan((beta)/(2)))