Find the equation of one of the sides of an isosceles right angled triangle whose hypotenuse is given by `3x + 4y =4` and the opposite vertex of the hypotenuse is `(2,2)`.

Show that in a right angled triangle, the hypotenuse is the longest side.

The equation of the circle circumscribing the triangle whose sides are the lines y = x + 2, 3y = 4x and 2y = 3x is ……

The line (x+6)/5=(y+10)/3=(z+14)/8 is the hypotenuse of an isosceles right-angled triangle whose opposite vertex is (7,2,4)dot Then which of the following in not the side of the triangle? a. (x-7)/2=(y-2)/(-3)=(z-4)/6 b. (x-7)/3=(y-2)/6=(z-4)/2 c. (x-7)/3=(y-2)/5=(z-4)/(-1) d. none of these

Find the direction cosines of the sides of the triangle whose vertices are (3, 5, – 4), (1, 1, 2) and (- 5, – 5, - 2).

Find equation of the circle passes through points (2,3) and (4,5) whose centre lies on the line y - 4x + 3 = 0.

In a right triangle, if the measure of an acute angle is 30^(@) , the side opposite to that angle is half the hypotenuse.

The altitude of a right triangle is 7 cm less than its base. If the hypotenuse is 13 cm , find the other two sides.

The ends of the hypotenuse of a right angled triangle are (6, 0) and (0, 6). Find the locus of the thrid vertex.

If A be the area of a right Deltaand b be one of the sides containing the right angle, prove that the length of the altitude on the hypotenuse is (2Ab)/(sqrt(b^(4)+4A^(2)) .

The altitude of a right triangle is 7 cm less than its base. If the hypotenuse is 13 cm, find the other two sides.