Calculate the shortest and longest wavelength of Balmer series of hydrogen atom. Given `R=1.097 xx 10^(7)m^(-1)`.

calculate the longest wavelength in Balmer series and the series limit . (Given R=1.097xx10^(7)m^(-1) )

Calculate the wavelength and wave numbers of the first and second lines in tbe Balmer series of hydrogen spectrum. Given R = 1.096xx10^(7) m^(-1)

The Rydberg constant for hydrogen is 1.097 X 10^(7) ms^(-1) . Calculate the short and long wavelength limits of Lyman series. Data: R=1.097xx10^(7)ms^(-1) For short wavelength limit of Lyman Series, n_(f)=1,n_(i)=oo, lambda_(s)=? For long wavelength limit of Lyman series, n_(f)=1, n_(i)=2, lambda_(i)=?

Calculate the wave number of the spectral line of shortest wavelength appearing in the Balmer series of H-spectrum. (R=1.09xx10^7m^(-1))

Calculate the wave number of the spectral line of shortest wave length appearing in Given R=1.09xx10^(7)m^(-1)

The wave number of the shortest wavelength transition in the Balmer series of H atom is