A parallel beam of light is incident on a face of a prism of refracting angle `60^@`. Find the refractive index of the prism if the angle of minimum deviation is 40. What is the new angle of minimum deviation if the prism is immersed in water of refractive index 1.33?

The angle of minimum deviation of a prism depends upon :

The refracting angle of a prism is A and refractive index of material of prism is cot (A)/(2) . The angle of minimum deviation is

For a prism of refractive index sqrt3 , the angle of the prism is equal to the angle of minimum deviation. The value of the angle of the prism is

A ray of light is incident normally on one of the faces of a prism of angle 30^@ and refractive index sqrt 2 . The angle of deviation of the ray is

A ray of light is incident normally on one of the faces of a prism of angle 30^@ and refractive index sqrt2 . The angle of deviation of the ray is

If the refractive index of a material of equilateral prism is sqrt3 , then angle of minimum deviation of the prism is

A prism is made of glass of unknown refractive index. A parallel beam of light is incident on a face of the prism. The angle of minimum deviation is measured to be 40^(@) . What is the refractive index of the material of the prism? The refracting angle of the prism is 60^(@) . If the prism is placed in water (refractive index 1.33), predict the new angle of minimum deviation of a parallel beam of light

How is angle of incidence related to the angle of minimum deviation?