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Write the nuclear reaction equation-for alpha decay of `""_(92)^(238)U`

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We are given the following atomic masses: ""_(92)^(238) U = 238.05079 u " " _(2)^(4)He = 4.00260 u ""_(90)^(234)Th = 234.04363 u" "_(1)^(1)H= 1.00783 u ""_(91)^(237)Pa = 237.05121 u Here the symbol Pa is for the element protactinium (Z = 91). (a) Calculate the energy released during the alpha decay of ""_(92)^(238)U . (b) Show that ""_(92)^(238)U can not spontaneously emit a proton.

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OSWAAL PUBLICATION-2020 Solved Paper I -Exercise
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  3. Write the nuclear reaction equation-for alpha decay of ""(92)^(238)U

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