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One face of a copper plateof area 5m^(2)...

One face of a copper plateof area `5m^(2)` and thickness 0.01m is in contact with water boiling at `100^(@)C`, the other face is at `0^(@)C`. Find the heat conducted in one second (K of copper `= 400 Wm^(-)K^(-1)`)

Text Solution

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`A = 5m^(2) , l = 0.01 m , K = 400 Wm^(-1) K^(-1)`
`theta_(1) = 100^(@)C , theta_(2) = 0^(@) C and t = 1s ` from `Q = (KA(theta_(1)-theta_(2)t))/(l) = (400 xx 5 xx (100 -0)xx1)/(0.01) = 2 xx 10^(7)J`
`rArr (2K_(2)A_(1)(theta_(1) - theta))/(l_(1)) = (K_(1)A(theta - theta_(2)))/(l_(1)) rArr 2 (theta_(1) - theta) = (theta - theta_(2))`
But `(theta_(1) - theta_(2)) = (theta_(1) + theta) + (theta - theta_(2)) rArr (theta_(1) - theta_(2)) = 3(theta_(1) - theta)`
`rArr (theta_(1) - theta) = ((theta_(1) - theta_(2))/(3)) = (36)/(3) = 12^(@)C" " therefore `i.e., temperature difference across the layes P is `12^(@)C`
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