Home
Class 11
PHYSICS
A spring of force constant K is cut into...

A spring of force constant K is cut into two parts whose lengths in the ratio 2: 3. The part having larger force constant is

A

Shorter spring

B

Longer spring

C

Both have equal force constants

D

Noting can be said

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • OSCILLATIONS

    AAKASH SERIES|Exercise EXERCISE -I Forced uscillations and resonance|9 Videos

  • OSCILLATIONS

    AAKASH SERIES|Exercise EXERCISE -I MORE THAN ONE ANSWERS QUESTIONS|6 Videos

  • OSCILLATIONS

    AAKASH SERIES|Exercise EXERCISE -I Simple pendulum|24 Videos

  • OSCILLATION

    AAKASH SERIES|Exercise QUESTIONS FOR DESCRIPTIVE ANSWERS|12 Videos

  • PHYSICAL WORLD

    AAKASH SERIES|Exercise VERY SHORT ANSWER TYPE QUESTIONS|5 Videos

Similar Questions

Explore conceptually related problems

A spring of force constant K is cut into two equal parts. The force constant of each part is,

A spring of force constant k is cut in to lengths of ratio 1:2:3. They are connected in series and the new force constant is k'. Then they are connected in parallel and force constant is k". Then k':k" is:

If a spring of force constant .K. is cut into three equal parts, then the force constant of each part will be

A spring of force constant 'K' is cut into two pieces such that one piece is double the length of the other. Then the long piece will have a force constant of