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A N-pole of a very long magnetic needle ...

A N-pole of a very long magnetic needle is placed at a distance of 20 cm from a point 'P'. If the pole strength of the magnetic needle is 40 Am what is the magnetic induction at the point 'P'?

Text Solution

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Since the magnetic needle is very long, the influence of S - pole can be neglected.
Pole strength of the needle, m = 40 Am.
Distance between the N-pole and the point P is r = 20 cm = `20 xx 10^(-2) m`
`:.` Magnetic induction due to the N-pole at P is
`B = (mu_0)/(4pi)(m)/(r^(2))=(4pi xx 10^(-7))/(4pi ) xx (40)/((20 xx 10^(-2))^(2))=10^(-4)T`
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