A 44 mH inductor is connected to 220 V, 50 Hz ac supply. Determine the rms value of current in the circuit.

Explanation

Here `L = 44mH = 44 xx 10^(-3)H`.
`v = 50 Hz`
`E_(rms) = 220 V`
Reactance of inductor.
`X_(L) = L omega = L xx 2pi v`
`= 44 xx 10^(-3) xx 2 xx 3.14 xx 50`
`= 13.82 Omega`
Current (rms) through the circuit
`I_(rms) = (E_(rms))/(X_(L)) = (220)/(13.82) = 15.9A`