When a capacitor of small capacitance is connected in series with L-R circuit. The alternating current in the circuit increases. Explain why ?

Explanation

Addition of capacitor in the given circuit decreases the impedance Z of the circuit and hence increases current I in the circuit as `I = (V)/(Z)`
where `Z = sqrt(R^(2) + X_(L)^(2))` without capacitor
and new `Z = sqrt(R^(2) + (X_(L) - X_(C))^(2))` with capacitor.