A carrier wave of 1000 W is subjected to `100%` modulation. Calculate (i) Power of modulated wave, (ii) Power in USB, (iii) Power in LSB.

Explanation

i)Total power of modulated wave
`P_(T)=P_(C)(1+(m^(2))/(2))=1000(1+(I^(2))/(2))=1500`watt
ii)Power in USB `=(1)/(2)P_(SB)`
Where power carried by side bands is given by amplitude Modulation and Detection
`P_(SB)=P_(C)((m^(2))/(2))=1000((l^(2))/(2))=1500` watt
`P_(USB)=(1)/(2)P_(SB)=(1)/(2)xx500=250` watt
`P_(LSB)=P_(USB)=250` watt