Home
Class 11
CHEMISTRY
What is Kc for the following equilibrium...

What is `K_c` for the following equilibrium when the equilibrium concentration of each substance is : `[SO_2]=0.60 M, [O_2]= 0.82M` and `[SO_3]` = 1.90 M ?
`2SO_(2(g)) + O_(2(g)) hArr 2SO_(3(g))`

Text Solution

Verified by Experts

`{:("Equilibrium reaction:", 2SO_(2(g)) +,O_(2(g)) hArr , 2SO_(3(g))),("Concentration at equili. (M)",0.6, 0.82 , 1.90):}`
Equilibrium constant of reaction is `K_c` ,
`K_c=[SO_3]^2/([SO_2]^2[O_2])=(1.90M)^2/((0.6M)^2(0.82M))`
`= 12.229 M^(-1)`
`= 12.229 "L mol"^(-1)`
Promotional Banner

Topper's Solved these Questions

  • EQUILIBRIUM

    KUMAR PRAKASHAN|Exercise SECTION-A Try Your self -2|6 Videos
  • EQUILIBRIUM

    KUMAR PRAKASHAN|Exercise SECTION-A Try Your self -3|10 Videos
  • ENVIRONMENT CHEMISTRY

    KUMAR PRAKASHAN|Exercise Question For Module (Section-C)|1 Videos
  • HYDROCARBONS

    KUMAR PRAKASHAN|Exercise (Questions for Module (Section - D))|1 Videos