At a certain temperature and total pressure of `10^5` Pa, iodine vapour contains 40% by volume of I atoms `I_(2(g)) hArr 2I_((g))` . Calculate `K_p` for the equilibrium.

Explanation

At equilibrium total pressure = `10^5` Pa
Partial pressure `prop` Percentage by volume of gas,
Concentration of atom of I = 40% by volume
`therefore p_1`=40% of (Total pressure)
`=(10)^5 (40//100)=0.40xx10^5` Pa
`p_(I_2)`= 60% of `10^5 =10^5 xx 0.60`
`=0.60xx10^5` Pa
Equilibrium reaction = `I_(2(g)) hArr 2I_((g))`
`therefore K_p=(p_I)^2/(p_(I_2))=(0.40xx10^5)^2/(0.60xx10^5)= 0.2667xx10^5`
`=2.667xx10^4` Pa