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At 600^@ NH4COONH(2(s)) hArr 2NH(3(g)) +...

At `600^@ NH_4COONH_(2(s)) hArr 2NH_(3(g)) + CO_(2(g))` is `K_p=3.2xx10^2 "bar"^3` of equilibrium constant , So, calculate `K_c`. (R=0.0831 L bar `K^(-1) "mol"^(-1)`)

Text Solution

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`2.5812xx10^(-3) ("mol"^(-1) L)^3`
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