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The 2.901 L saturated solution is formed...

The 2.901 L saturated solution is formed by 0.08 g `CaF_2` at 298 K temp. then calculate `K_(sp)` (Molecular moles of `CaF_2` is 78 g `"mol"^(-1)`)

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`1.715xx10^(-10)`
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KUMAR PRAKASHAN-EQUILIBRIUM-SECTION-A Try Your self -10
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  6. The K(sp) of CaF2 is 1.7 xx 10^(-10). Then what is the volume in milil...

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  8. The pH of saturated solution of Ca(OH)2 is 12.25. Then calculate its s...

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  9. The concentration of saturated solution of Mg(OH)2 is 8.2 xx 10^(-4) %...

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  10. The solution is 2L of 0.02 M NaOH . The solubility product of Zn(OH)2 ...

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  12. 0.08 g/2.901 L is a saturated solution of CaF2 at 298 K temp. calculat...

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  13. The K(sp) of BaSO4 is 1.1 xx 10^(-10), Will a precipitate form when eq...

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  14. The concentration of 500 ML NaOH solution is 0.02 M. How many grams of...

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  15. Predict whether a precipitate of PbI2 will be formed or not on mixing ...

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  16. If the [F^-] = 2.0 xx 10^(-5) M in water. Then, how many gram of CaCl2...

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  17. [Ag^+] in solution is 1 xx 10^(-6) M then what is the concentration o...

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  18. At 298 K temp., the solubility product for AgCl is 1.5xx10^(-10) .Calc...

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  19. The solubility of AgCl is 1.435xx10^(-5) gL^(-1) at 30^@C temp. then c...

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  20. The solubility of CaF2 in water is 1.7xx10^(-3) g/100 mL at 298 K temp...

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