In which equilibrium it will `K_p=K_c`.
(i)`CaCO_(3(s)) hArr CaO_((s)) + CO_(2(g))`
(ii)`2HI_((g)) hArr H_(2(g)) + I_(2(g))`
(iii)`N_(2(g)) + 3H_(2(g)) hArr 2NH_(3(g))`
(iv)`C_((s)) + O_(2(g)) hArr CO_(2(g))`
(v)`PCl_(5(g)) hArr PCl_(3(g)) + Cl_(2(g))`
(vi)`CO_((g)) + H_2O_((g)) hArr CO_(2(g)) + H_(2(g)) `

Explanation

In (ii),(iv), and (vi), `K_p=K_c` because `Deltan_((g))`=zero