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In this reaction CO((g)) + H2O((g)) hArr...

In this reaction `CO_((g)) + H_2O_((g)) hArr CO_(2(g)) + H_(2(g))` initially [CO]=0.1 M and at equilibrium [CO]=0.067 M so, if `K_c`=4.24 than what will be the value of `K_p` ?

Text Solution

Verified by Experts

`K_p=K_c=4.24`
as `Deltan_((g))=0,K_p = (K_c)(RT)^(Deltan)`
`therefore K_p=K_c`
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KUMAR PRAKASHAN-EQUILIBRIUM-SECTION-B OBJECTIVE QUESTIONS
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