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(NH4)2 CO(3(s)) hArr 2NH(3(g)) + CO(2(g)...

`(NH_4)_2 CO_(3(s)) hArr 2NH_(3(g)) + CO_(2(g)) + H_2O_((g))`
If the total pressure is P at equilibrium then what will be the volume of equilibrium constant, `K_p` in a closed vessel ?

A

`P^4/64`

B

`P^3/32`

C

`(4P^3)/27`

D

`P^3/64`

Text Solution

Verified by Experts

The correct Answer is:
A
Total pressure =P
`K_P=(P_(NH_3))^2 xx (P_(CO_2))xx(P_(H_2O))`
`=((2P)/4)^2 xx (P/4) xx (P/4)=P^4/64`
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