The value of `K_c` for the reaction
`2HI_((g)) hArr H_(2(g)) + I_(2(g))` is `1xx10^(-4)`
At a given time, the composition of reaction mixture is (HI] = `2 xx 10^(-5)` mol, `[H_2] = 1 xx 10^(-5)` mol and `[I_2] = 1 xx 10^(-5)` mol
In which direction will the reaction proceed ?

Explanation

Given for , `[HI]=2xx10^(-5)` mol
`[H_2] = 1xx10^(-5)` mol
`[I_2]= 1xx10^(-5)` mol
At a given time, the reaction quotient Q for the reaction will be given by the expression
`Q=([H_2][I_2])/[HI]^2`
`=(1xx10^(-5) xx 1xx10^(-5))/(2xx10^(-5))^2=1/4=0.25 =2.5xx10^(-1)`
If the value of reaction quotient is more than the value of `K_c`. i.e., `1 xx 10^(-4)` the reaction will proceed in the reverse reaction.