Show that for a first order reaction, `t_(99.9%)=10t_(1//2)`. 

Show that for first order reaction t(87.5%) = 3t_(50%)

Show that for a first order reaction the time required for 99.9% completion is about 10 times its half life period.

The rate for a first order reaction is 0.6932 xx 10^(-2) mol " "L^(-1) and the initial concentration of the reactant is 1M, t_(1//2) is equal to

Show that in case of a first order reaction, the time taken for completion of 99.9% reaction is ten times the time required for half change of the reaction.

The rate constant of a first order reaction is 1.15 xx 10^(-3)s^(-1) . Calculate its half life period (t1//2) .

What is half life period of a reaction ? Show that half of a first order reaction is independent of initial concentration.

Rate constant of a first order reaction is 0.0693 min^(-1) . Calculate the percentage of the reactant remaining at the end of 60 minutes.

The initial rate of a first order reaction is 5.2 xx 10^(-6)" mol.lit"^(-1).s^(-1) at 298 K. When the initial concentration of reactant is 2.6xx10^(-3)" mol.lit"^(-1) , calculate the first order rate constant of the reaction at the same temperature.